hujiulong / gcoord Goto Github PK
View Code? Open in Web Editor NEW地理坐标系转换工具
License: MIT License
地理坐标系转换工具
License: MIT License
使用<script src="https://unpkg.com/gcoord/dist/gcoord.js"></script>
引入时出现Cannot find "/dist/gcoord.js" in [email protected]
的错误。
Here is already one, just want to know dose this refer it or not? https://github.com/wandergis/coordtransform
ionic 3 中通过npm 下载后,启动项目提示:
typescript: node_modules/gcoord/dist/types/transform.d.ts, line: 1
Cannot find module './geojson'.
L1: import { Position, GeoJSON } from './geojson';
下载下来还要build。。
Throws an exception: Uncaught Error: fromCRS is invalid
var pointStr = "113.98245404505606,22.52280474";
let point = pointStr.split(',');
var result = gcoord.transform(
point, // 经纬度坐标
gcoord.BD09, // 当前坐标系
gcoord.WGS84 // 目标坐标系
);
console.log(point);//["113.98245404505606", "22.52280474"]
console.log(result);//[113.97106644180005, 22.519655815769017]
var result2 = gcoord.transform(
point, // 经纬度坐标
gcoord.GCJ02, // 当前坐标系
gcoord.WGS84 // 目标坐标系
);
console.log(result2);//["113.98245404505606", "22.52280474"]
BD09转换GCJ02坐标后,大概会有15-30米左右的一个偏移,这是一个正常的偏移量么?
[{ "longitude": 112.95516973717, "latitude": 27.110248315429 }, { "longitude": 112.95514967002, "latitude": 27.110209045353 }, { "longitude": 112.9552696853, "latitude": 27.110439072645 }, { "longitude": 112.95538827008, "latitude": 27.11055600291 }, { "longitude": 112.95552789901, "latitude": 27.110607549457 }, { "longitude": 112.95563435193, "latitude": 27.110608671425 }, { "longitude": 112.95591453403, "latitude": 27.110596723704 }, { "longitude": 112.95625794057, "latitude": 27.110520645541 }, { "longitude": 112.95637142166, "latitude": 27.110518640771 }, { "longitude": 112.9565491395, "latitude": 27.110464491862 }, { "longitude": 112.95693074252, "latitude": 27.11043674701 }, { "longitude": 112.95795897797, "latitude": 27.110248575302 }, { "longitude": 112.95866190586, "latitude": 27.110180202997 }, { "longitude": 112.95943518443, "latitude": 27.110209670777 }, { "longitude": 112.96032802743, "latitude": 27.110363173252 }, { "longitude": 112.96197014333, "latitude": 27.11084511094 }, { "longitude": 112.96234773516, "latitude": 27.110922743543 }, { "longitude": 112.96382982801, "latitude": 27.111144138779 }, { "longitude": 112.96614400844, "latitude": 27.111540288631 }, { "longitude": 112.96689684702, "latitude": 27.111625778344 }, { "longitude": 112.96737860852, "latitude": 27.111681353588 }]
rt
目前gcoord主要是做两件事:转换坐标系和生成geojson格式的对象
但是第二个功能似乎必要性不大,两个功能之间的关联性也不强,可以考虑移除掉geojson相关代码
移除这部分代码不会影响到transform处理geojson格式的坐标
支持墨卡托投影坐标
#include<stdio.h>
#include<math.h>
#include<stdlib.h>
#define PI 3.1415926535897932384626
double a = 6378245;
double ee = 0.006693421622965823;
// roughly check whether coordinates are in China.
int isInChinaBbox(double lon, double lat){
return lon >= 72.004 && lon <= 137.8347 && lat >= 0.8293 && lat <= 55.8271;
}
double transformLat(double x, double y){
double ret = -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y + 0.2 * sqrt(fabs(x));
ret += ((20.0 * sin(6.0 * x * PI) + 20.0 * sin(2.0 * x * PI)) * 2.0) / 3.0;
ret += ((20.0 * sin(y * PI) + 40.0 * sin((y / 3.0) * PI)) * 2.0) / 3.0;
ret += ((160.0 * sin((y / 12.0) * PI) + 320.0 * sin((y * PI) / 30.0)) * 2.0) / 3.0;
return ret;
}
double transformLon(double x, double y){
double ret = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1 * sqrt(fabs(x));
ret += ((20.0 * sin(6.0 * x * PI) + 20.0 * sin(2.0 * x * PI)) * 2.0) / 3.0;
ret += ((20.0 * sin(x * PI) + 40.0 * sin((x / 3.0) * PI)) * 2.0) / 3.0;
ret += ((150.0 * sin((x / 12.0) * PI) + 300.0 * sin((x / 30.0) * PI)) * 2.0) / 3.0;
return ret;
}
double* delta(double lon, double lat){
double *d = (double *)malloc(2*sizeof(double));
double dLon = transformLon(lon - 105.0, lat - 35.0);
double dLat = transformLat(lon - 105.0, lat - 35.0);
double radLat = (lat / 180.0) * PI;
double magic = sin(radLat);
magic = 1.0 - ee * magic * magic;
double sqrtMagic = sqrt(magic);
d[0] = (dLon * 180.0) / (a / sqrtMagic * cos(radLat) * PI);
d[1] = (dLat * 180.0) / ((a * (1.0 - ee)) / (magic * sqrtMagic) * PI);
return d;
}
double* WGS84ToGCJ02(double lon_WGS, double lat_WGS){
double *GCJ = (double *)malloc(2*sizeof(double));
if (!isInChinaBbox(lon_WGS, lat_WGS)){
GCJ[0] = lon_WGS;
GCJ[1] = lat_WGS;
return GCJ;
}
double *d = delta(lon_WGS, lat_WGS);
GCJ[0] = lon_WGS + d[0];
GCJ[1] = lat_WGS + d[1];
return GCJ;
}
double* GCJ02ToWGS84(double lon_GCJ, double lat_GCJ) {
double *WGS = (double *)malloc(2*sizeof(double));
if (!isInChinaBbox(lon_GCJ, lat_GCJ)){
WGS[0] = lon_GCJ;
WGS[1] = lat_GCJ;
return WGS;
}
WGS[0] = lon_GCJ; WGS[1] = lat_GCJ;
double *temp = WGS84ToGCJ02(WGS[0], WGS[1]);
double dx = temp[0] - lon_GCJ;
double dy = temp[1] - lat_GCJ;
while (fabs(dx) > 1e-6 || fabs(dy) > 1e-6) {
WGS[0] -= dx;
WGS[1] -= dy;
temp = WGS84ToGCJ02(WGS[0], WGS[1]);
dx = temp[0] - lon_GCJ;
dy = temp[1] - lat_GCJ;
}
return WGS;
}
int main(){
double lon, lat;
double x = 114.5048503, y = 37.0705911;
double *q = GCJ02ToWGS84(x, y);
printf("%.10lf %.10lf\n", q[0], q[1]);
getchar();
}
在china-cities.json中随机选取一份数据
"WGS84": [114.498916, 37.0700925],
"GCJ02": [114.5048503, 37.0705911],
使用我的代码将GCJ02转换为WGS84,结果为[114.4989213554, 37.0700966574]
不知道是不是你的算法写错了,还是我重写的代码出了问题,我反复对照了多遍,没发现有遗漏的地方。希望得到你的回复。
百度地图,和腾迅,还有高德还是有点差距,
我试了下百度的坐标转换,发现精度对不上
"WGS84" :121.18180305555556, 31.287874444444444 转"BD09"
百度自带的结果为:121.19272701709394,31.29222496103614
库的结果为:121.19272205711691,31.292220583538928
这会不会是js精度带来的问题?
transform参数不支持通过网页获取到对应的当前坐标系和待转换坐标系的value 来传入方法中吗?
理论上,GCJ-02的加密过程是不可逆的,但是可以通过一些方法来逼近接原始坐标,并且这种方式的精度很高。gcoord使用的纠偏方式达到了厘米级的精度,能满足绝大多数情况
引用wiki上的这句话,可以公布下通过哪些方法来逼近接原始坐标吗?(只是个人疑问)
希望可以推出不同坐标下瓦片的转换(比如在wgs84坐标的地图上,加载在线的互联网地图会偏移)
需求是,可以矫正一些互联网地图到标准的地图上。
思路是,通过请求的url中的 {x}/{y}/{z}通过scale或者solution和zoom等计算(定位)出wgs84的瓦片的 四至,转换四至的坐标到在线地图的坐标下,再通过在线地图的坐标,计算出在线地图的瓦片。(如有错误请指正)
import gcoord from 'gcoord';
编译出来的代码会发现 gcoord 找不到
Cannot read properties of undefined (reading 'transform')
必须改成这样才行
import * as gcoord from 'gcoord';
改成这样后,语法提示又出错了。比较别扭,不知道是哪里的问题。
IE浏览器:不支持“isNaN” 报错TypeError: 对象不支持“isNaN”属性或方法
var result = gcoord.transform(
[121.41473785401124, 31.076902617360464 ], // 经纬度坐标
gcoord.BD09, // 当前坐标系
gcoord.GCJ02 // 目标坐标系
)
console.log(result);
从BD09到WGS84
gcoord.transform(geojson, gcoord.BD09, gcoord.WGS84);
转换前:
{
"type": "Polygon",
"coordinates": [
[
[
110.30060468148584,
21.219847338501882
],
[
110.31066570319426,
21.18898007297982
],
[
110.31440265411453,
21.20111209125531
],
[
110.31857079167945,
21.214995275091464
],
[
110.30865349885258,
21.21769088580071
],
[
110.30060468148584,
21.219847338501882
]
]
]
}
转换后:
{
"type": "Polygon",
"coordinates": [
[
[
110.27907103222238,
21.212303455167472
],
[
110.29982281199085,
21.18536961030313
],
[
110.30355067508778,
21.19756068173438
],
[
110.3077014913672,
21.211509795833887
],
[
110.29783559081969,
21.214053794383407
],
[
110.27907103222238,
21.212303455167472
]
]
]
}
能支持把各种坐标系转换为直角坐标系的功能吗?
海外位置偏差,纬度:34.6937378经度:135.5021651,坐标系wgs84
应该国内国外判断出现问题导致
When the coordinate is transferred to GPS coordinates, there is no change.
For example:
var geojson = {
"type": "Point",
"coordinates": ["120.42378", "27.452646"]
}
gcoord.transform(geojson, gcoord.GCJ02, gcoord.WGS84);
目前 gps 坐标 转 百度地图坐标,偏移很大,而且存在缩放问题,请问是否有办法解决?
国家大地2000坐标系支持吗?
我有一个Typescript的开源项目,可以转换JSON 到GeoJSON, 支持转换其他attribute。或许你可以拿去用。
程序到坐标转换这个方法直接死了
现在好多地图都开始使用大地2000的经纬坐标
大地2000 和WGS84是否有差别
如果有能否增加一个大地2000 和各个经纬度的转换
您好,GCJ-02 - 国测局坐标和CGCS2000对应吗?谢谢!
比如设置成保留6位小数?
如题,大家有用到Cesium吗,现在我在Cesium上调用高德,谷歌**,腾讯,百度地图,然后调用腾讯的poi接口,得到的poi兴趣点中的经纬度,显示在高德,谷歌**,腾讯的底图上都没问题,但是显示在百度地图的底图就有偏差了,调用了转换还是偏差很大。不知道大家是怎么处理这个问题的?
gcoord.transform(
[loc.lng, loc.lat], // 经纬度坐标
gcoord.GCJ02, // 当前坐标系
gcoord.BD09// 目标坐标系
)
import gcoord : import gcoord from "gcoord";
use gcoord:
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