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View Code? Open in Web Editor NEW算法——1找零(多少组合方式)
算法——1找零(多少组合方式)
问题:给定不同面额的硬币 coins 和一个总金额 amount。计算可以凑成总金额所需的组合数。如果没有任何一种硬币组合能组成总金额,返回 0。 例 1: coins = [1, 2, 5], amount = 5, result =4 (5=2+2+1=2+1+1+1=1+1+1+1) 例 2: coins = [2], amount = 3, result = 0 说明:每种硬币的数量是无限的。 解法 一看到找零问题,马上反应用动态规划,只要知道<amount金额的解,就能马上得出金额为amount的解 时间复杂度 时间空间都是O(nm)
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