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圖片標記數量

您好我想請問:
1.yolo2coco這份轉換code支援一張圖片還有多個物件 txt檔有對應各物件的眶嗎
還是說他只能一張圖片 一個標記框呢

annotations id 错误。

你好,感谢提供代码。我在使用的时候发现annotatios中的id 对应的变量i没有相对应的计算,这样在使用pycocotools读取时会出错。
‘’‘
dataset['annotations'].append({
'area': width * height,
'bbox': [x1, y1, width, height],
'category_id': int(cls_id),
'id': i,
'image_id': k,
'iscrowd': 0,
# mask, 矩形是从左上角点按顺时针的四个顶点
'segmentation': [[x1, y1, x2, y1, x2, y2, x1, y2]]
})
‘’‘

你的代码太没效率了,我改了下,现在8秒钟就跑完,原先要3个小时

"""
author: Wu
2021/1/24
source: https://github.com/Weifeng-Chen/DL_tools/blob/main/coco2yolo.py
COCO 格式的数据集转化为 YOLO 格式的数据集,源代码采取遍历方式,太慢,
这里改进了一下时间复杂度,从O(nm)改为O(n+m),但是牺牲了一些内存占用
--json_path 输入的json文件路径
--save_path 保存的文件夹名字,默认为当前目录下的labels。
"""

import os 
import json
from tqdm import tqdm
import argparse

parser = argparse.ArgumentParser()
parser.add_argument('--json_path', default='./instances_val2017.json',type=str, help="input: coco format(json)")
parser.add_argument('--save_path', default='./labels', type=str, help="specify where to save the output dir of labels")
arg = parser.parse_args()

def convert(size, box):
    dw = 1. / (size[0])
    dh = 1. / (size[1])
    x = box[0] + box[2] / 2.0
    y = box[1] + box[3] / 2.0
    w = box[2]
    h = box[3]

    x = x * dw
    w = w * dw
    y = y * dh
    h = h * dh
    return (x, y, w, h)

if __name__ == '__main__':
    json_file =   arg.json_path # COCO Object Instance 类型的标注
    ana_txt_save_path = arg.save_path  # 保存的路径

    data = json.load(open(json_file, 'r'))
    if not os.path.exists(ana_txt_save_path):
        os.makedirs(ana_txt_save_path)
    
    id_map = {} # coco数据集的id不连续!重新映射一下再输出!
    for i, category in enumerate(data['categories']): 
        id_map[category['id']] = i

    # 通过事先建表来降低时间复杂度
    max_id = 0
    for img in data['images']:
        max_id = max(max_id, img['id'])
    # 注意这里不能写作 [[]]*(max_id+1),否则列表内的空列表共享地址
    img_ann_dict = [[] for i in range(max_id+1)] 
    for i, ann in enumerate(data['annotations']):
        img_ann_dict[ann['image_id']].append(i)

    for img in tqdm(data['images']):
        filename = img["file_name"]
        img_width = img["width"]
        img_height = img["height"]
        img_id = img["id"]
        head, tail = os.path.splitext(filename)
        ana_txt_name = head + ".txt"  # 对应的txt名字,与jpg一致
        f_txt = open(os.path.join(ana_txt_save_path, ana_txt_name), 'w')
        '''for ann in data['annotations']:
            if ann['image_id'] == img_id:
                box = convert((img_width, img_height), ann["bbox"])
                f_txt.write("%s %s %s %s %s\n" % (id_map[ann["category_id"]], box[0], box[1], box[2], box[3]))'''
        # 这里可以直接查表而无需重复遍历
        for ann_id in img_ann_dict[img_id]:
            ann = data['annotations'][ann_id]
            box = convert((img_width, img_height), ann["bbox"])
            f_txt.write("%s %s %s %s %s\n" % (id_map[ann["category_id"]], box[0], box[1], box[2], box[3]))
        f_txt.close()

語意分割的YOLO如何轉COCO

作者你好
由於yolov5跟yolov7都有出了語意分割(segmentation),因此save_txt的內容,就不像傳統的只有bbox xywh值
而是有多個點組成的polygon

不曉得作者您能否做一個polygon的yolo(txt)轉COCO (json)方式
謝謝

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