The _printf() function takes one argument:

A string with / without specifiers to print and gives the output formatted.

The string is printed character by character and when founds a '%' with a letter calls one of that parameters and print them instead the specifiers.

• Recreation printf Function
  • Description
  • Table of Content
  • Usage
  • Format Specifiers
  • Future Features
  • Bugs
  • Examples
  • Authors
  • License

Like the according main.h library version:

int _printf(const char *format, ...);

Format generators are a format with which we tell the function to take the arguments ​​according to the indicated type.

A format specifier follows this prototype: %type The following format specifiers are supported:

• %b : The specifier %b doesn't work all correctly

#include "main.h"

int main (void)
{
    _printf ("I am a character %s", 'F');

    return (0);
}

Output : I am a character F

#include "main.h"

int main (void)
{

    _printf ("%s", "STRING");

    return (0);
}

Output : STRING

#include "main.h"

int main (void)
{

    _printf ("I am percentage %%");

    return (0);
}

Output : I am a percentage %

#include "main.h"

int main (void)
{

    _printf ("I am an integer %i", 10);

    return (0);
}

Output : I am an integer 10

#include "main.h"

int main (void)
{

    _printf ("I am a binary %b", 54);

    return (0);
}

Output : I am a binary 110110

• Diego Linares Castillo. ([email protected])
• Luis Manrique Chávez. ([email protected])

MIT