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Hi All-
Could you please help me converting the cell centered value to node points? I want to export x, y, z, and field from my plt data but my field is cell centered and x,y,z is nodal points. Could you please help me with script on PYTecplot.

Thanks!

Do i have to make any changes in the Time average script for "variables to be averaged" And "constant variables"?

When I am running this script tecplot is crashing

After a bit of experimenting with the tpmath.py, compute_average function, i found that the script gives error if a variable is locked (e.g. by CFD ANALYZER).
is there a way to check if the variable is locked?
if the user does not know about this, such as me, it was much frustration because when the code reaches the following line, it gives error
tp.data.operate.execute_equation("{%s} = 0"%(v.name), zones=[avg_zone])
i think it could be avoided by using constant_variables?

Hey,
I'm having an issue with a macro similar to Convert_SolutionTime.mcr:

$!AlterData [|current_zone|]
Equation = '{Normal_temp} = {CoordinateX} / cos(0.919680578714)'
$!ActiveFieldMaps = [|current_zone|]
$!GETVARNUMBYNAME |temp_num|
NAME = "Normal_temp"
$!AlterData [|current_zone|]
Equation = '{Normal_Coordinate} = {Normal_temp} - |MINVAR[|temp_num|]|'

The macro crashes with:

" >, <. >=, <=, &&, || ==, != are only allowed in first parameter of the IF() function.

If you are using '<' or '>' for MAX or MIN, please change this to use the MAX() or MIN() functions.

Example:
Change {a}>{b} to MAX({a},{b})
Change {a}<{b} to MIN({a},{b}).

Error occurred near position marked with "@" below:

@{Normal_Coordinate} = {Normal_temp} - |MINVAR[20]| "

So that leaves me with the question, why it correctly determines |temp_num| to be 20 but is unable to perform the equation. If i manually changed |temp_num| to 20 it works. Do I have to cast |temp_num| to some other sort of datatype? Also I don't have an IF statement in my macro so I don't get the crash message.

Convert_SolutionTime.mcr actually works in pretty much the same way but for him it seems to work?

Any help would be appreciated!

The macro for Lambda2 criterion is almost correct, except line 18 for s2o2_13.

It should be
{s2o2_13} = {s11}{s13} + {s12}{s23} + {s13}{s33} + {Omga12}{Omga23},
instead of
{s2o2_13} = {s11}{s13} + {s12}{s23} + {s13}{s33} - {Omga12}{Omga23}.

The minus sign usually came from the antisymmetric property of Omega.
Therefore, matrix Omega*Omega (1,3) = Omega(1,2)Omega(2,3), which does not involve minus sign.
For cases like OmegaOmega (2,3) = Omega(2,1)*Omega(1,3) = - Omega(1,2)*Omega(1,3). We have minus sign here.