Multivariable Linear Regression in Go (golang)
$ go get github.com/sajari/regression
Supports Go 1.8+
Import the package, create a regression and add data to it. You can use as many variables as you like, in the below example there are 3 variables for each observation.
package main
import (
"fmt"
"github.com/sajari/regression"
)
func main() {
r := new(regression.Regression)
r.SetObserved("Murders per annum per 1,000,000 inhabitants")
r.SetVar(0, "Inhabitants")
r.SetVar(1, "Percent with incomes below $5000")
r.SetVar(2, "Percent unemployed")
r.Train(
regression.DataPoint(11.2, []float64{587000, 16.5, 6.2}),
regression.DataPoint(13.4, []float64{643000, 20.5, 6.4}),
regression.DataPoint(40.7, []float64{635000, 26.3, 9.3}),
regression.DataPoint(5.3, []float64{692000, 16.5, 5.3}),
regression.DataPoint(24.8, []float64{1248000, 19.2, 7.3}),
regression.DataPoint(12.7, []float64{643000, 16.5, 5.9}),
regression.DataPoint(20.9, []float64{1964000, 20.2, 6.4}),
regression.DataPoint(35.7, []float64{1531000, 21.3, 7.6}),
regression.DataPoint(8.7, []float64{713000, 17.2, 4.9}),
regression.DataPoint(9.6, []float64{749000, 14.3, 6.4}),
regression.DataPoint(14.5, []float64{7895000, 18.1, 6}),
regression.DataPoint(26.9, []float64{762000, 23.1, 7.4}),
regression.DataPoint(15.7, []float64{2793000, 19.1, 5.8}),
regression.DataPoint(36.2, []float64{741000, 24.7, 8.6}),
regression.DataPoint(18.1, []float64{625000, 18.6, 6.5}),
regression.DataPoint(28.9, []float64{854000, 24.9, 8.3}),
regression.DataPoint(14.9, []float64{716000, 17.9, 6.7}),
regression.DataPoint(25.8, []float64{921000, 22.4, 8.6}),
regression.DataPoint(21.7, []float64{595000, 20.2, 8.4}),
regression.DataPoint(25.7, []float64{3353000, 16.9, 6.7}),
)
r.Run()
fmt.Printf("Regression formula:\n%v\n", r.Formula)
fmt.Printf("Regression:\n%s\n", r)
}Note: You can also add data points one by one.
Once calculated you can print the data, look at the R^2, Variance, residuals, etc. You can also access the coefficients directly to use elsewhere, e.g.
// Get the coefficient for the "Inhabitants" variable 0:
c := r.Coeff(0)You can also use the model to predict new data points
prediction, err := r.Predict([]float64{587000, 16.5, 6.2})Feature crosses are supported so your model can capture fixed non-linear relationships
r.Train(
regression.DataPoint(11.2, []float64{587000, 16.5, 6.2}),
)
//Add a new feature which is the first variable (index 0) to the power of 2
r.AddCross(PowCross(0, 2))
r.Run()
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