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Solutions for Daily Coding Problem.
class Node:
def __init__(self, key):
self.left = None
self.right = None
self.val = key
def createTree(arr):
if not arr:
return None
mid = len(arr)//2
node = Node(arr[mid])
node.left = createTree(arr[:mid])
node.right = createTree(arr[mid+1:])
return node
def findSecondHighest(root):
if root:
global max, smax
current = root.val
if current > max:
max, smax = current, max
elif current < max and current > smax:
smax = current
findSecondHighest(root.left)
findSecondHighest(root.right)
sorted_nums = [1, 2, 3, 4, 15, 6, 17, 8]
tree = createTree(sorted_nums)
smax = tree.val
max = tree.val
findSecondHighest(tree)
print(smax)
This works, but could you advise on how could I do better, or at least how could I avoid those global variables.
Hi there,
Regarding the problem #1, i am wondering in the second method why not check the remaining value against the primary array and not in knownnumbers.
Is there any specific case which i am missing?
lists = [[10, 15, 30], [12, 15, 20, 31], [17, 20, 32]]
one_sorted_list = []
for i in range(len(lists)):
one_sorted_list = sorted([ *one_sorted_list, *lists[i] ])
print(one_sorted_list)
The first challenge has a simpler way of writing out a solution, in my opinion, which you may want to consider adding:
from itertools import combinations
def determine_sum(numbers, neededSum):
resulting_values = list(map(sum combinations(numbers, 2)))
if neededSum in resulting_values:
return True
return False
This though I think is technically two passes rather than one, which may make it less ideal for the challenge
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