Application of Breadth-First Search to see if a directed graph is Strongly Connected

• Vertex u and v are mutually reachable if there is a path from u to v and also a path from v to u
• A directed graph is strongly connected if every pair of nodes is mutually reachable

• Run BFS from any vertex
• Make G^rev, a new graph with edge directions reversed
• Run BFS on G^rev
• Return true iff every vertex is reachable in both BFS on G and BFS on G^rev

• Make a new StrongConnectivity() object
• Create a graph as an ArrayList<ArrayList<Integer>> Adjacency List
  • Each graph.get(u) is an ArrayList<Integer> of vertices representing edges going From u
  • Vertex names are simply increasing integer values, no need for human-readable vertex ID's like S or T
  • Graph adjacency list must have all edges represented
  • If there are no outgoing edges from a vertex, add an empty ArrayList
graph2.add(new ArrayList<Integer>());
• Call isStronglyConnected() and pass in a graph
  boolean isGraph1StronglyConnected = strongConnectivityFinder.isStronglyConnected(graph1);

• isStronglyConnected() always chooses vertex 0 to start BFS, but that's completely arbitrary

• Strong Connectivity - Richard Zanibbi
• Strong Connectivity - Kevin Wayne
• Strong Connectivity - Jaehyun Park