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javastructures's Issues

关于stack有点疑问

我在calculatePostfixValue类中看到的一段

查看来自后端架构师技术图谱 的 栈

         //postifx = "1392-*+9+";
         char ch=postfix.charAt(i);
          if (ch>='0' && ch<='9')
          {
              result=0;
              while (ch!=' ')
              {
                  //将整数字符转为整数值ch=90
                  result = result*10 + Integer.parseInt(ch+"");
                  i++;
                  ch = postfix.charAt(i);
              }
              i++;
              stack.push(result);//操作数入栈
          }

这里的Integer.parseInt(ch+"");不会报错?
这里while 里面的ch = postfix.charAt(i);,不是会读取到操作符吗
result*10这个也没明白

关于执行AVLTree#remove(T data)后不平衡的问题

测试代码:

public static void main(String[] args) {
    AVLTree<Integer> t = new AVLTree<>();
    t.insert(70);
    t.insert(40);
    t.insert(10);
    t.insert(100);
    t.insert(120);
    t.insert(130);
    t.insert(140);
    t.insert(150);
    t.insert(160);
    t.insert(135);
    t.insert(170);
    t.insert(145);
    t.remove(160);
}

即执行完上述代码后树形由:
image

变为:
image

可见节点170这棵子树是不平衡的

/ src / com / zejian / structures / LinkedList / singleLinked / SingleILinkedList.java 的 public boolean removeAll(T data)问题

//原来代码 存在问题 如果有多个data 包括头节点时
@OverRide
public boolean removeAll(T data) {

    boolean isRemove=false;

    if(this.head!=null&&data!=null){

        //如果移除的是头结点
        if(data.equals(this.head.data)){
            this.head=this.head.next;
            isRemove=true;
        }else {

            Node<T> front=this.head;
            Node<T> pre=front.next;
            //查找所有数据相同的结点并删除
            while (pre!=null){

                if(data.equals(pre.data)){
                    //更改指针指向
                    front.next=pre.next;
                    pre =front.next;
                    isRemove=true;
                }else {
                    front=pre;
                    pre=pre.next;
                }
            }
        }
    }else {//data=null || this.head=null
        isRemove=false;
    }
    return isRemove;
}

//修改后代码
@OverRide
public boolean removeAll(T data) {
boolean isRemove = false;

    if(this.head != null && data != null){
        //如果移除的是头节点
        if(data.equals(this.head.data)){
            this.head = this.head.next;
            isRemove = true;
        }
        
        Node<T> front = this.head;
        Node<T> pre = front.next;
        //查找所有数据相同的节点并删除
        while(pre != null){
            if(data.equals(pre.data)){
                front.next = pre.next;
                pre = front.next;
                isRemove = true;
            }else {
                front = pre;
                pre = pre.next;
            }
        }

    }
    return isRemove;
}

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