Challenge time! You are going to use what you've learned so far to solve the famous FizzBuzz Coding Challenge. The challenge is one of the most common coding interview questions.
Here's the FizzBuzz challenge.
- Create a new file called
fizzbuzz.py:
# Write a program that prints the numbers from 1 to 100.
# But for multiples of three print "Fizz" instead of the number
# and for the multiples of five print "Buzz".
# For numbers that are multiples of both three and five print "FizzBuzz".
# Tip: % (modulo) tells you what's left over when you divide one number by another
# ex. number % 3 == 0Good luck!
Here's the answer to FizzBuzz in Python. Hopefully, you gave the FizzBuzz challenge a try. Whether you got the solution or not, let's work through the logic together.
- First print out the numbers from 1 to 100:
for number in range(1,101):
print(number)- Print "Fizz" if the number is divisible by 3:
for number in range(1,101):
if number % 3 == 0:
print("Fizz")
else:
print(number)- Print "Buzz" if the number is divisible by 5:
for number in range(1,101):
if number % 3 == 0:
print("Fizz")
elif number % 5 == 0:
print("Buzz")
else:
print(number)- Print "FizzBuzz" if the number is divisible by 3 and 5:
for number in range(1,101):
if number % 3 == 0 and number % 5 == 0:
print("FizzBuzz")
elif number % 3 == 0:
print("Fizz")
elif number % 5 == 0:
print("Buzz")
else:
print(number)(Note that this new condition number % 3 == 0 and number % 5 == 0 has to go above the other two because otherwise the others run first.)
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