prdx23 / acrylic Goto Github PK

The comment for Schemes.scheme says the default for fuzzy is 0:

But it's coming in with a default value of -1:

Causing it to randomize the complementary colors returned:

Things like Color(name='red'), Color(name='blue')

Hi

I can not get accurate (or, well, "good enough") complementary colors of RYB colors. I tried looking into the code, but couldn't find where that is done.
It is accurate if I'd want the complementary of blue, yellow or red. But it feels like, in the conversion from rgb to ryb or back, there is no mapping done via trilinear interpolation or whatnot. (Interpolation between fixed conversion points on the ryb spectrum) I found that other programs do that. There is a C program I almost thought about porting to python, but I really have no idea what I'm doing.

What I do is:

• Get tuple rgb color and make it acrylic
• do a scheme complementary with "in_rgb=False" (and "fuzzy=0" because default is "-1" but there is another issue for that)
• (find out that the resulting format now requires you to write: "color[0].rgb" instead of "color.rgb")
• give back rgb code

    colorPx = (53, 53, 53)
    colorPx = acrylic.Color(rgb = (colorPx[0], colorPx[1], colorPx[2]))                        # colorPx = Color(rgb=(53, 53, 53))
    colorPx = colorPx.scheme(acrylic.Schemes.COMPLEMENTARY, in_rgb=False, fuzzy=0)             # colorPx = [Color(hsl=(0.0, 0.0, 20.78))] ... it's now a list with Color inside
    colorPx = acrylic.Color(ryb = (colorPx[0].ryb[0], colorPx[0].ryb[1], colorPx[0].ryb[2]))   # colorPx = Color(ryb=(202, 202, 202))
    colorPx = (colorPx.rgb[0], colorPx.rgb[1], colorPx.rgb[2])                                 # colorPx = (53, 53, 53) (bad example)

(I didn't want to create other variables just for this, so I used the same again and again)

I also tried converting to a ryb tuple after creating a acrylic.color (color.ryb[0], 1 ,2...), then creating another acrylic.color but this time it's "ryb = ...", do the scheme conversions, create another ryb tuple (this time with color[0].ryb[0] , 1 , 2..) Convert it to a rgb tuplr and look at that. But it's of course identical.

I can never get these complementary colors from the ryb example here: https://en.wikipedia.org/wiki/Complementary_colors

Besides that: I feel like the result when I convert to RGB or something else via colorPx = acrylic.Color(ryb = (colorPx[0], colorPx[1], colorPx[2])).rgb giving the result back in the format of Rgb(r=46, g=45, b=42) is very annoying, for me at least. I see the value in having a Rgb I can get r out of via color.Rgb.r, maybe. If that is even the correct way. Sorry, these fundamental things necessary to start programming are beyond me. :) (That's why I'm not doing that up there in the code)
But if I'm not inserting three variables I shouldn't get three variables out. Int in int out. Well... you know what I mean.

Greetings