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linear-algebra-and-learning-from-data's Issues

Problem I.1.6 mistake

In Problem I.1.6, in the second solution for D there is a mistake in the computation.

Let the corners of the parallelogram are: $A=(1,1)$,  $B=(1,3)$, $C=(4,2)$, the fourth corner is $D$. There are three possible values for $D$,
[...]
* If $BD=AC$, then $D = B + BD = B + AC =  B + (C-A) = (4,2) + (3, 1) = (7, 3)$

In the last step B+(C-A) = (4,2) + (3, 1) = (7, 3), B=(1,3) seems to have been confused with C=(4,2).

I believe it should read B+(C-A) = (1,3) + (3, 1) = (4, 4)

Reposting

Dear Neil,

may I repost your content on my website (with proper citations)?

1.9.2 Solution

I believe there is a mistake in the solution for the closest rank-1 matrix to the matrix [[2, 1], [1, 2]].

It should be 3/2 [[1, 1], [1, 1]]. I think you left out the multiplication by the sigma term 3.

5.1.6 solution

Hello, I believe there is a mistake in the variance calculation -- the mean m should be subtracted from each x before squaring. Though I did not go through them, it looks like this may apply to 5.1.4 and 5.1.5 as well.

Suggested answer

Dear @niuers,
Thank you for posting your solutions, they help a lot!
Can I offer one that is still work in progress? It's on section III.3, question 6 (Sylvester eq.)
III_3_q6

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