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JD signature algorithm implemented by python
Hi, all!
When I start test.py using my parameters, I get next response:
{"code":"604","echo":"decrypt failed"}
What does this mean?
Is signature generated with no errors?
url中的uuid是加密过的吧,是传加密过的还是原始的?
如果是原始的,需要怎么获取?如果是取随机值然后再加密uuid的话怎么加密呢?
另外我试了functionID=gentoken的情况是验证失败,可以给个例子吗谢谢!
现在抓的包里面没有了uuid,需要怎么获取呢
请求里的screen uuid build 等都是加密后的参数 请问现在还有方式获取到吗
你好,用抓包参数生成出来的sign和原始请求上的不一致啊
不能用,大家可以看我主页
好像没办法使用
{"code":"601","echo":"Queuing","tips":"活动参与太热情,正在努力加载,片刻后为您呈现~","wait":"5"}
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