but all you do is translate from the alphabet list (tern) to numeric value (data list) and vice versa but that ain't no trytes or tryte conversion as far as i can see, if that is what you want to do. perhaps search on github for python projects which already do this? otherwise going after this:
https://steemit.com/iota/@wiredcrypto/understanding-iota-trits-and-trytes
# we can hardcode it like this
iota_alphabet = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z', '9']
# or generate it somewhat like this
import string
iota_alphabet = list(string.ascii_uppercase)
iota_alphabet.append(9)
# we know it's 27 characters long, A-Z and a 9, so we could just hardcode 27
remainder = ascii_val % 27
# or get it's length
remainder = ascii_val % len(iota_alphabet)
tryte_val_two = (ascii_val - remainder) / 27
# or again getting the length
tryte_val_two = (ascii_val - remainder) / len(iota_alphabet)
# this gives us a float val, we need an int
# so we make it one
tryte_val_two = int((ascii_val - remainder) / len(iota_alphabet))
# could also be done when getting the char from the list like this
iota_alphabet[int(tryte_val_two)]
# now we have the two characters for the trye, or at least their index in the alphabet
# let's get this done
tryte = iota_alphabet[remainder] + iota_alphabet[tryte_val_two]
looks great, but doesn't help that much in this cluttered fashion, so let's put this together in a function
def char_to_tryte(char):
ascii_val = ord(char)
# tc1 should be an int, but for good measure we make sure it will be one
tc1 = int(ascii_val % len(iota_alphabet))
tc2 = int((ascii_val - tc1) / len(iota_alphabet))
tryte = iota_alphabet[tc1] + iota_alphabet[tc2]
return tryte
print(char_to_tryte('H'))
SC
# ascii_val -> 72
# tc1 -> 18
# tc2 -> 2
this is working and gives us the right numbers but the return value looks kinda wrong. we wanted RB and got SC. luckily we know python lists start at 0, not 1. so what we need to do is subtract 1 from our values somewhere. either directly while getting them or while using them as list indices
# as list indices:
def char_to_tryte(char):
ascii_val = ord(char)
# tc1 should be an int, but for good measure we make sure it will be one
tc1 = int(ascii_val % len(iota_alphabet))
tc2 = int((ascii_val - tc1) / len(iota_alphabet))
tryte = iota_alphabet[tc1 - 1] + iota_alphabet[tc2 - 1]
return tryte
# while getting the numbers
def char_to_tryte(char):
ascii_val = ord(char)
# tc1 should be an int, but for good measure we make sure it will be one
tc1 = int((ascii_val % len(iota_alphabet)) - 1)
tc2 = int(((ascii_val - tc1) / len(iota_alphabet)) - 1)
tryte = iota_alphabet[tc1] + iota_alphabet[tc2]
return tryte
print(char_to_tryte('H'))
# now gives us
RB
# when subtracting from list indices
# ascii_val -> 72
# tc1 -> 18
# tc2 -> 2
# when subtracting while getting our numbers
# ascii_val -> 72
# tc1 -> 17
# tc2 -> 1
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