OSTEP-操作系统导论 答案 Operating Systems: Three Easy Pieces
OSTEP-操作系统导论 答案 Operating Systems: Three Easy Pieces
操作系统导论（中文版）
注：只有部分章节包含作业。开源书有部分章节比中文出版书作业更多，这里仅按照中文出版书中的出现的作业回答。
在书中，题目的要求是
creates a pointer to an integer, sets it to NULL, and then tries to dereference it
，也就是创建一个指向NULL的指针并且dereference它。根据C++ Dereferencing中的解释，dereference就是取值的意思，所以题目的要求应该是尝试访问这个指针，因此代码应该类似于：
int *p = NULL;
int i = *p;而非在创建指针后将其free。
第1个job，响应时间：0
第2个job，响应时间：1x量子长度
第3个job，响应时间：2x量子长度
...
第N个job，响应时间：（N-1）x量子长度
avg响应时间 = [0+1+2+...+（N-1）]x量子长度 = （N-1）/2 x 量子长度
你好，我想问问在习题中出现的这段代码：
sub $1, %bx
test $0, %bx
jgt .top其中的test指令的作用是什么，我感觉作者想表达的应该是cmp指令，即和0进行比较，比0大就继续循环。
但是根据我对test指令的了解，它是对两个参数进行与运算，可是任何数和0相与不都是0吗，这样对条件码的影响会和cmp相同吗？
我看到你的答案里好像也是按照cmp理解的，所以我有些困惑，是我对test指令理解错了吗？
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