[BUG] ArgumentError: malformed expression in formula about rcall.jl HOT 3 OPEN

I am currently using the following workaround/fix

function RCall.rcopy(::Type{RCall.FormulaTerm}, l::Ptr{RCall.LangSxp})
    expr = RCall.rcopy(Expr, l)
    if Meta.isexpr(expr, :call) && length(expr.args) == 2 && expr.args[1] == :~
        # special case of simple variable, like in aes(x, y)
        return expr
    end
    # complex formular
    return @eval RCall StatsModels.@formula($expr)
end

from rcall.jl.

I don't know if the example here is artificial, but I'm not sure I think it makes sense to try to copy the result of aes(x, y) into Julia. Here's my reasoning and guess what I thinking is going wrong:

• aes(x, y) is an example of non-standard evaluation in R -- the x and the y are treated as symbols and not as variables and then those symbols are evaluated in the context of the dataframe you pass into the rest of the ggplot2 call. Julia doesn't have non-standard evaluation -- and intentionally so. Non-standard evaluation is really great for some bits of fun syntax (like the tidyverse uses extensively), but it's very hard for humans and compilers to reason about and thus very hard or even impossible to optimize. This is part of why efforts to add a bytecode compiler to R have had very limited success.[1] In other words, the R expression aes(x, y) has no direct Julia analog and not just because aes is an R function and not a Julia one.
• Julia relies instead on macros to do syntax rewriting and thus implement things like the Wilkinson-Roger notation, i.e. the formula syntax.
• If I recall correctly (it's been a while since I messed with ggplot2 internals and much has changed in the mean time), aes and the like are actually rewritten into a mix of formula notation and things like aes_ which doesn't use non-standard evaluation. My guess is that when this happens, then x gets turned into the one-sided formula ~ x.
• RCall sees this formula and says "aha, I know how to translate a formula!" and calls into StatsModels, which has the canonical Julia implementation of the Wilkinson-Roger notation via its @formula macro. The only problem is that there are no one-sided formulae in this implementation. I haven't talked to @kleinschmidt to know for sure why, but my guess is that this partly related to
  • there are other ways to construct individual terms in Julia
  • there are other ways in Julia to do the types that R uses one-sided formulae for
  • macros can do syntactic rewriting, but the original input still has to be valid Julia syntax, even if it's not "semantically" correct because Julia parses the expression before the macro gets to manipulate it.
• If you really need a one-sided formula in Julia, then you do something like @formula(0 ~ x)
• Now that we've covered why your example doesn't work, I'm not sure it's a good idea to try it. I can't see how aes(x, y) is useful in Julia -- it's an entity that's meant to be consumed by ggplot2's functions and, as far as I know, there are no functions in Julia that can consume it. So if you just need a reference to the aes-entity to later pass it back into R, then you don't need to call rcopy -- you can just do aes = reval("aes(x, y)") and you'll have a Julia reference to the object in R.

If there's some cool use case I'm missing, please let me know! Then I could provide more guidance. 😄

One final "nit" -- for the example you're using here, you don't need the whole tidyverse, just ggplot2. Trimming the dependency stack can really help track down a problem, so just FYI. ❤️

from rcall.jl.

Very impressive detailed answer. Indeed there is a usecase: I am in the process of supporting R in Pluto via RCall. Quite a special usecase, but of course in such a generic "execute some R code via RCall" setting, these cases just happen.

In other words: why should rcopy be left to fail in some known (or unkown) cases? Better let's make it valid in all cases.

from rcall.jl.