Comments (8)
GetPage里面设置popGesture: false可以解决
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GetPage里面设置popGesture: false可以解决
这个一刀切有点不符合我这边的逻辑,我这边的场景就类似打开一个只有一个webview的页面,webview加载了很多层的url,侧滑返回时要让webview.goback(),webview不能回退时再侧滑就退出当前页面。
就差不多是这样的,根据不同情况来判断处理侧滑事件
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试试这两:
adaptive_will_pop_scope
adaptive_pop_scope
我感觉在iOS上拦截侧滑是个很奇怪的事情,侧滑本身已经触发了动画,这时候拦截掉,体验不是很友好
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same same
from getx.
试试这两: adaptive_will_pop_scope adaptive_pop_scope
我感觉在iOS上拦截侧滑是个很奇怪的事情,侧滑本身已经触发了动画,这时候拦截掉,体验不是很友好
不好意思,这几天太忙没看,这个拦截侧滑就是要在侧滑开始之前拦截啊,不是已经发生侧滑了才拦截。WillPopScope就是处理这种的,监听到这个动作的时候可以让你决定在onWillPop返回是否可以侧滑
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Same to me
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return PopScope(
canPop: false,
child: Scaffold(
appBar: AppBar(
leading: BackButton(onPressed:() => Get.back(),), 问题解决了 canPop: false,然后自定义BackButton事件;
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我这边也是一样的情况,我想根据一个变量去判断是否可以侧滑退出
WillPopScope(
onWillPop: widget.logic.state.isSelect ? () async => false : null,
child: Container()
);
之前在WillPopScope上可以正常运作的。但是升级到PopScope就无法实现我这边想要的功能
修改后如下
PopScope(
canPop: widget.logic.state.isSelect, // 这里测试无论是true还是false,IOS都可以侧滑返回
onPopInvoked: (didPop){
print(didPop);
},
child: Container()
);
@weigoudan 不过我这边回退到WillPopScope还是能够保留原始功能的,不像你说的设置true还是false都会侧滑退出,惹不起惹不起
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