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Comments (8)

xiajie0 avatar xiajie0 commented on July 4, 2024

GetPage里面设置popGesture: false可以解决

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weigoudan avatar weigoudan commented on July 4, 2024

GetPage里面设置popGesture: false可以解决

这个一刀切有点不符合我这边的逻辑,我这边的场景就类似打开一个只有一个webview的页面,webview加载了很多层的url,侧滑返回时要让webview.goback(),webview不能回退时再侧滑就退出当前页面。
就差不多是这样的,根据不同情况来判断处理侧滑事件

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xiajie0 avatar xiajie0 commented on July 4, 2024

试试这两:
adaptive_will_pop_scope
adaptive_pop_scope

我感觉在iOS上拦截侧滑是个很奇怪的事情,侧滑本身已经触发了动画,这时候拦截掉,体验不是很友好

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yanashenyang avatar yanashenyang commented on July 4, 2024

same same

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weigoudan avatar weigoudan commented on July 4, 2024

试试这两: adaptive_will_pop_scope adaptive_pop_scope

我感觉在iOS上拦截侧滑是个很奇怪的事情,侧滑本身已经触发了动画,这时候拦截掉,体验不是很友好

不好意思,这几天太忙没看,这个拦截侧滑就是要在侧滑开始之前拦截啊,不是已经发生侧滑了才拦截。WillPopScope就是处理这种的,监听到这个动作的时候可以让你决定在onWillPop返回是否可以侧滑

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lalayiersan avatar lalayiersan commented on July 4, 2024

Same to me

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qiuyan81 avatar qiuyan81 commented on July 4, 2024
return PopScope(
  canPop: false,
  child: Scaffold(
            appBar: AppBar(
              leading: BackButton(onPressed:() => Get.back(),),   问题解决了 canPop: false,然后自定义BackButton事件;

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zhushenwudi avatar zhushenwudi commented on July 4, 2024

我这边也是一样的情况,我想根据一个变量去判断是否可以侧滑退出

WillPopScope(
      onWillPop: widget.logic.state.isSelect ? () async => false : null,
      child: Container()
);

之前在WillPopScope上可以正常运作的。但是升级到PopScope就无法实现我这边想要的功能

修改后如下

PopScope(
      canPop: widget.logic.state.isSelect, // 这里测试无论是true还是false,IOS都可以侧滑返回
      onPopInvoked: (didPop){
          print(didPop);
      },
      child: Container()
);

@weigoudan 不过我这边回退到WillPopScope还是能够保留原始功能的,不像你说的设置true还是false都会侧滑退出,惹不起惹不起

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