An easy way to require all files within a directory.
var controllers = require('require-all')({
dirname : __dirname + '/controllers',
filter : /(.+Controller)\.js$/,
excludeDirs : /^\.(git|svn)$/,
recursive : true
});
// controllers now is an object with references to all modules matching the filter
// for example:
// { HomeController: function HomeController() {...}, ...}If your objective is to simply require all .js and .json files in a directory you can just pass a string to require-all:
var libs = require('require-all')(__dirname + '/lib');If your directory contains files that all export constructors, you can require them all and automatically construct the objects using resolve:
var controllers = require('require-all')({
dirname : __dirname + '/controllers',
filter : /(.+Controller)\.js$/,
resolve : function (Controller) {
return new Controller();
}
});If your directory contains files where the names do not match what you want in the resulting property (for example, you want camelCase but the file names are snake_case), then you can use the map function. The map function is called on both file and directory names, as they are added to the resulting object.
var controllers = require('require-all')({
dirname : __dirname + '/controllers',
filter : /(.+Controller)\.js$/,
map : function (name, path) {
return name.replace(/_([a-z])/g, function (m, c) {
return c.toUpperCase();
});
}
});
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