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License: Apache License 2.0
Make Structs Easy (MSE)
License: Apache License 2.0
I absolutely love this package! I'm far from being a Spark/Scala pro but it makes my live so much easier working with jsons and transforming them.
However, executing it with Spark 3.1 and Scala 2.12 I am getting the following error:
java.lang.NoSuchMethodError: scala.Predef$.refArrayOps([Ljava/lang/Object;)Lscala/collection/mutable/ArrayOps;
How can I make it available for Spark 3.x? Thx!
Consider the following spark-shell
session, which has loaded the latest published version of both this library, and spark-hofs
.
import com.github.fqaiser94.mse.methods._
import za.co.absa.spark.hofs._
import spark.implicits._
val jsonText = """{
| "data1": [
| {
| "vlan": {
| "id": "195",
| "name": "Subnet-54.14.195"
| }
| },
| {
| "vlan": {
| "id": "195",
| "name": "Subnet-54.14.193"
| }
| }
| ]
| }""".stripMargin
val df = spark.read.option("multiline", "true").json(Seq(jsonText).toDS())
# this works fine
df.withColumn("data1", transform($"data1", col => col.withFieldRenamed("vlan", "vlan_renamed"))).printSchema
# but what if I want to rename "name" to "device_name" ?
# I thought it would be something like this
df.withColumn("data1", transform($"data1", col => col.withField("vlan", $"data1.vlan".withFieldRenamed("name", "device_name")))).printSchema
# but it fails with:
org.apache.spark.sql.AnalysisException: cannot resolve 'rename_fields(`data1`.`vlan`, 'name', 'device_name')' due to data type mismatch: Only struct is allowed to appear at first position, got: array.;;
'Project [transform(data1#44, lambdafunction(add_fields(lambda elm#58, vlan, rename_fields(data1#44.vlan, name, device_name)), lambda elm#58, false)) AS data1#57]
+- LogicalRDD [data1#44], false
I believe that the problem might be here. If this is an array
, then we should descend into the elementType
to see if it's a StructType
. Does this seem on the right track, or am I off the mark?
Hello All,
I am using spark-submit to submit a job by modifying a nested struct column by adding a new field using withField()
Following is the spark-submit command:
spark-submit --master local --packages com.github.fqaiser94:mse_2.11:0.2.4 --py-files mse.zip write_data.py
I have ziped mse, since I dont want to install it globally and also I am going to execute it in AWS EMR.
I am getting following error:
Traceback (most recent call last):
File "/Users/fkj/DataLakeManagement/archive/write_data.py", line 3, in
from mse import *
File "/Users/fkj/DataLakeManagement/archive/mse.zip/mse/init.py", line 1, in
File "/Users/fkj/DataLakeManagement/archive/mse.zip/mse/methods.py", line 5
def __withField(self: Column, fieldName: str, fieldValue: Column):
^
SyntaxError: invalid syntax
Following is my mse.zip:
write_data.py:
from datetime import datetime
from mse import *
from pyspark.sql import SparkSession
from pyspark.sql import functions as f
from pyspark.sql.types import StructType, StringType, TimestampType, IntegerType
def spark():
"""
This function is invoked to create the Spark Session.
:return: the spark session
"""
spark_session = (SparkSession
.builder
.appName("Data_Experimentation_Framework")
.getOrCreate())
spark_session.conf.set("spark.sql.parquet.outputTimestampType", "TIMESTAMP_MILLIS")
return spark_session
address = StructType().add("state", StringType())
schema = StructType().add("_id", IntegerType()) \
.add("employer", StringType()) \
.add("created_at", TimestampType()) \
.add("name", StringType())\
.add("address", address)
employees = [{'_id': 1,
'employer': 'Microsoft',
'created_at': datetime.now(),
'name': 'Noel',
'address': {
"state": "Pennsylvania"
}
},
{'_id': 2,
'employer': 'Apple',
'created_at': datetime.now(),
'name': 'Steve',
'address': {
"state": "New York"
}
}
]
df = spark().createDataFrame(employees, schema=schema)
df.withColumn("address", f.col("address").withField("country", f.lit("USA")))
df.printSchema()
df.write \
.format("parquet") \
.mode("append") \
.save("/Users/felixkizhakkeljose/Downloads/test12")
Could you help me to identify what am I doing wrong?
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