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evenMai92 avatar evenMai92 commented on July 22, 2024

方法一
思路:

  • 当字符串数组长度为 0 时则公共前缀为空,直接返回
  • 令最长公共前缀 ans 的值为第一个字符串,进行初始化
  • 遍历后面的字符串,依次将其与 ans 进行比较,两两找出公共前缀,最终结果即为最长公共前缀
  • 如果查找过程中出现了 ans 为空的情况,则公共前缀不存在直接返回
  • 时间复杂度:O(s),s 为所有字符串的长度之和
var longestCommonPrefix = function(strs) {
    let n = strs.length;
    if(n === 0) return '';
    let ans = strs[0];
    for(let i = 1; i < n; i++) {
        let j = 0
        for(; j < ans.length && j < strs[i].length; j++) {
            if(ans[j] !== strs[i][j]) {
                break;
            }
        }
        ans = ans.substr(0, j);
        if(ans === '') return '';
    }
    return ans;
};
作者:guanpengchn
链接:https://leetcode-cn.com/problems/longest-common-prefix/solution/hua-jie-suan-fa-14-zui-chang-gong-gong-qian-zhui-b/
来源:力扣(LeetCode)

from front-end-interview.

evenMai92 avatar evenMai92 commented on July 22, 2024

官方题解

from front-end-interview.

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