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License: Other
Calendrical Calculations in Python
License: Other
I haven't yet seen the book define the maximum date the lisp routines support. However, based on the function call result in the example below, the maximum Gregorian year should be 2938 or less (at least for the Hindu functions). Once the value is clear, it would be nice if the maximum date (or year) supported was provided by the source code.
>>> import pycalcal as pcc
>>> pcc.hindu_lunar_holiday(9, 1, 2939)
[]
The Gregorian years in ephemeris_correction
for the various bounds are much lower than 2938 (i.e., 2019 is the highest Gregorian year, in the first if statement), so the problem above is likely due to the limitations of that function. However, there may be other limitations too.
I am new to Github and programming.
Excuse me if I am writing this at an inappropriate place.
I am looking for a pre-compiled Calendrical Calculation program, so that it can run on my windows PC.
Thanks for your help
I think I succeeded in porting PyCalCal for Python 3 with a version which works for Python 2 and Python 3.
So, if somebody is interested to test that version, thank you to let my a message.
Good weekend.
pgr123
The url : http://calendrica.appspot.com/ is giving 404.
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