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Automatically exported from code.google.com/p/dmfa07
Suppose I have a vector
y = [1 2 1 2 5].
Then, there obviously is a group of 4 in the first 4 elements of the vector
using, say, eps = 1.
However, running
> dbscan(y', 4, 1)
ans =
-1 -1 -1 -1 -1
which is clearly not what is intended. However, the following works:
> dbscan(y', 3, 1)
ans =
1 1 1 1 -1
Original issue reported on code.google.com by [email protected]
on 29 Nov 2012 at 3:28
Suppose we have the vector
y = [1 1 1 2 3 4]
Then, with eps = 1 and k = 4 we clearly expect that 3 to be on the boundary of
the group formed by [1 1 1 2]. By algorithm definition, 3 is not allowed to
propagate group membership. However, we find that
>> [a,b] = dbscan(y', 3, 1)
a =
1 1 1 1 1 1
b =
1 1 1 1 0 0
where 3 did propagate the group membership to 4. 4 However should be classified
as an outlier. (Note that I entered k-1 to dbscan, as explained in my other bug
report.
Original issue reported on code.google.com by [email protected]
on 29 Nov 2012 at 3:35
hi, I need your help.
I have downloaded your code DBSCAN.M and has renamed it in dbscan.m to use the
code in Octave because I don't have Matlab.
Now I want to use the code on a dataset with 8 objects having 2 attributes. My
file sees like that :
1 2
2 3
4 5
2 1
3 4
2 2
1 3
5 5
I think that this is the right codage for the file but when i will use your
clusteringfigs as mention in your example, i receive always an error saying
'clusteringfigs' undefined.
Can you help me and say me where the problems lies and how i can fix it?
Thanks
Original issue reported on code.google.com by [email protected]
on 18 May 2011 at 1:01
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