albertofaria / bdus Goto Github PK
View Code? Open in Web Editor NEWA framework for implementing Block Devices in User Space
Home Page: https://bdus.readthedocs.io
License: GNU General Public License v2.0
A framework for implementing Block Devices in User Space
Home Page: https://bdus.readthedocs.io
License: GNU General Public License v2.0
Will there be an effort to upstream the kernel module or is the focus here to be out of tree ?
When I build dbus with some errors,should sove for it?
make -C /lib/modules/4.18.0-193.el8.x86_64/build M='/test/bdus-0.1.1/kbdus' W=1 C=0 DEBUG=0
make[1]: 进入目录“/usr/src/kernels/4.18.0-193.el8.x86_64”
CC [M] /test/bdus-0.1.1/kbdus/src/control.o
CC [M] /test/bdus-0.1.1/kbdus/src/device.o
/test/bdus-0.1.1/kbdus/src/device.c: 在函数‘kbdus_device_ioctl_create_buffer_’中:
/test/bdus-0.1.1/kbdus/src/device.c:523:34: 错误:宏“access_ok”传递了 3 个参数,但只需要 2 个
argument_usrptr, size))
^
In file included from /test/bdus-0.1.1/kbdus/src/device.c:8:
/test/bdus-0.1.1/kbdus/include-private/kbdus/utilities.h:45:43: 错误:‘access_ok’未声明(在此函数内第一次使用)
#define kbdus_access_ok(type, addr, size) access_ok((type), (addr), (size))
^~~~~~~~~
/test/bdus-0.1.1/kbdus/src/device.c:520:10: 附注:in expansion of macro ‘kbdus_access_ok’
if (!kbdus_access_ok(
^~~~~~~~~~~~~~~
/test/bdus-0.1.1/kbdus/include-private/kbdus/utilities.h:45:43: 附注:每个未声明的标识符在其出现的函数内只报告一次
#define kbdus_access_ok(type, addr, size) access_ok((type), (addr), (size))
^~~~~~~~~
/test/bdus-0.1.1/kbdus/src/device.c:520:10: 附注:in expansion of macro ‘kbdus_access_ok’
if (!kbdus_access_ok(
^~~~~~~~~~~~~~~
make[2]: *** [scripts/Makefile.build:313:/test/bdus-0.1.1/kbdus/src/device.o] 错误 1
make[1]: *** [Makefile:1542:module/test/bdus-0.1.1/kbdus] 错误 2
make[1]: 离开目录“/usr/src/kernels/4.18.0-193.el8.x86_64”
make: *** [Makefile:45:kbdus.ko] 错误 2
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