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GoogleCodeExporter avatar GoogleCodeExporter commented on June 12, 2024
There are a couple reasons why they're coming out different. First, when you 
use a string for the key, then it's treated as a passphrase from which to 
derive a pseudo-random key and IV. To get the same ciphertext both times, you'd 
have to supply an actual key and IV. Second, when you use CryptoJS 2 to create 
a WordArray from "message", you need to tell it how many bytes are significant, 
otherwise it will use all eight bytes within the two 32-bit words, rather than 
just the seven bytes that is in your message. And third, the stringToBytes and 
bytesToWords methods of CryptoJS 2 can be replaced by Latin1.parse of CryptoJS 
3, which will also automatically handle the significant bytes issue. This 
should work for you:

var key = CryptoJS.lib.WordArray.random(256/8);
var iv = CryptoJS.lib.WordArray.random(256/8);

a = CryptoJS.AES.encrypt("message", key, { 'iv': iv });
w = CryptoJS.enc.Latin1.parse("message");
b = CryptoJS.AES.encrypt(w, key, { 'iv': iv });

Also, in the future, the more appropriate spot for this question is the 
discussion group.

Original comment by Jeff.Mott.OR on 6 Sep 2012 at 4:36

  • Changed state: Invalid

from crypto-js.

GoogleCodeExporter avatar GoogleCodeExporter commented on June 12, 2024
Thanks for quick answer! Tho my real question was: how to encrypt byte array 
same way as Java ciphers does? But as suggested I'll use discussion group for 
this one.

Original comment by [email protected] on 6 Sep 2012 at 4:57

from crypto-js.

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