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Java-via avatar Java-via commented on June 3, 2024

回答问题:
def keyOnly(a, *b, c)def keyOnly(a, c, *b)含义不同,前者c必须使用关键字匹配,后者c等同普通参数,可使用关键字匹配也可位置匹配。另外*b是一个tuple,具体可看后面例子。
def keyOnly(a, *, b, c)里面的*,我理解的是一个特殊标识,其后所有参数必须使用关键字匹配。

看例子:

# 例1
def keyOnly(a, *b, c): 
    print(a, b, c)

keyOnly(1, 2, 3)  # 报错   | c是必须使用关键字匹配的
keyOnly(1, 2, c=3)   # 1 (2,) 3   | a位置匹配了1,c关键字匹配了3,剩余部分都给b
keyOnly(1, 2, 3, c=4)   # 1 (2, 3) 4   | a位置匹配了1,c关键字匹配了4,剩余部分都给b


# 例2
def keyOnly(a, *, b, c): 
    print(a, b, c)`

keyOnly(1, 2, 3)    # 报错  | b,c必须关键字匹配
keyOnly(1)   # 报错  | b,c不可缺少
keyOnly(1, b=2, c=3)  # 1,2,3  | b,c使用了关键字匹配
# 说明:*后面的参数,必须使用关键字匹配,而且在没有默认值的情况下必须使用关键字传入


# 例3
def keyOnly(a, *, b=1): 
    print(a, b)
keyOnly(1)  # 1,1   | 这里跟例2的区别是b有默认值
keyOnly(1, 2)  # 报错   | b必须使用关键字匹配
keyOnly(1, b=2)  # 1,2   | b使用了关键字匹配

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andyRon avatar andyRon commented on June 3, 2024

@Java-via
这样理解都没问题。我也是这样理解。但是实际定义时都是语法错误

In [513]: def keyOnly(a, *b, c):
  File "<ipython-input-513-33899a4618ce>", line 1
    def keyOnly(a, *b, c):
                       ^
SyntaxError: invalid syntax


In [514]: def keyOnly(a, *, b, c):
  File "<ipython-input-514-6c4803bea73d>", line 1
    def keyOnly(a, *, b, c):
                    ^
SyntaxError: invalid syntax


In [515]: def keyOnly(a, *, b=1):
  File "<ipython-input-515-787a0f504685>", line 1
    def keyOnly(a, *, b=1):
                    ^
SyntaxError: invalid syntax

我记得函数参数定义的顺序是:必选参数、默认参数、可变参数和关键字参数,这边的*b*是必须放在后面的。 我用的是2.7,不知道是不是3.x之后没有这个规定?

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xianhu avatar xianhu commented on June 3, 2024

2.x版本不支持。

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andyRon avatar andyRon commented on June 3, 2024

@xianhu 估计就是这个问题! phper学习python,见笑了,谢谢!

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Java-via avatar Java-via commented on June 3, 2024

@xianhu 无限期待3.6向前兼容

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