Comments (4)
There is not a single Promax rotation, but indefinitely many: it depends on m. You can choose a "weak" or "strong" rotation, with larger m resulting in stronger rotations. In a nutshell, the Promax power parameter m enhances the effect of driving smaller eigenvector values even more towards 0 by raising the values to the power m. The larger m, the more you will discriminate lower values from larger values.
An Example
Take two eigenvector values, 0.4 and 0.6, obtained from Varimax rotation. Raise both to the power of m=2: 0.16 and 0.36. Alternatively, raise both to the power of, say, m=5: 0.01 and 0.08.
In the Varimax solution, the second value was 50% larger than the first value. With Promax m=2, the second value is 125% larger. And with Promax m=5, the second value is 700% larger. So the power parameter effectively controls the relative importance of individual values.
In summary, higher values of the Promax power parameter m will result in solutions that focus more on the important eigenvector values, at the cost of introducing more correlation between the principal component (PC) scores, which are uncorrelated for Varimax.
Many thanks for the knowledege and your time to answer this question. I believe I had an improved understanding on the m impact on the effect of the Rotation.
from xeofs.
No worries! Did you have a look into the review paper of Richmann (1986)? In section 8.5 he describes the Promax procedure. In particular, he defines the elements of target matrix of the Procrustes transformation as
where
In xeofs, the power parameter EOFRotator
class represents
from xeofs.
No worries! Did you have a look into the review paper of Richmann (1986)? In section 8.5 he describes the Promax procedure. In particular, he defines the elements of target matrix of the Procrustes transformation as
bij=|aijm+1|/aij
where aij are the elements of the matrix obtained by Varimax rotation. For m=1, you simply get bij=aij, i.e. the Varimax solution. For m≥1, the bij will differ from aij and, in general, the obtained matrix won't be orthogonal anymore.
In xeofs, the power parameter p of the
EOFRotator
class represents m. Does that clear up the confusion?
Thanks for the quickreply, I haven't looked into that paper. I will have a look of it soon. BTW, a quick question: what is the difference of m=3 and m=4 if I want to get a Promax REOF?
from xeofs.
There is not a single Promax rotation, but indefinitely many: it depends on
An Example
Take two eigenvector values, 0.4 and 0.6, obtained from Varimax rotation. Raise both to the power of
In the Varimax solution, the second value was 50% larger than the first value. With Promax
In summary, higher values of the Promax power parameter
from xeofs.
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from xeofs.