Switch out require(underscore) for lodash about blendid HOT 4 CLOSED

I'll make a pull request later.

from blendid.

Except that, having located the offending require('underscore'), I find myself at a loss as to what purpose it serves.

There's a comment in package.json that goes:

The following 'underscore' example demonstrates exposing a module included by another module. If you were to npm install underscore separately and require('underscore'), you'd end up with two copies in your bundle. The one you installed, and the one that shipped with another package (backbone in this example). This is an edge case and should rarely happen.

The 'plugin' example makes that file requireable with require('plugin'), and available to browserify-shim as 'plugin' on line 30.

If I understand this correctly, it's saying that ... well, I haven't actually figured it out. How would backbone be installing its own copy of underscore without npm or bower?

I guess I'm asking, what purpose does this aliasing of underscore to backbone/node_modules/underscore accomplish?

from blendid.

so when you npm install backbone, it brings its own copy of underscore with it. You can see it if you open up node_modules/backbone - you'll see underscore in there. If the only thing you required in a js file was backbone, and you opened up the compiled file, you'd see backbone.js AND underscore.js in the bundle. If you also npm install underscore, and require 'underscore', you'd end up with backbone's copy + the copy you installed from npm. It's an edge case I ran into, and I thought I'd call it out here. I know it's not super clear though. I may end up yanking that example since most people just get confused by it. Make sense?

from blendid.

That does make sense now.

...

It also sheds more light on your comment the other day. Thanks for the followup!

from blendid.