Section 4.6 about conv_arithmetic HOT 6 CLOSED

We use the tildes to differentiate the direct convolution view of the transposed convolution from the transposed convolution view itself.

I'm pretty sure the equation in relationship 13 is correct (you can verify that by solving the equation in relationship 6 for i, which corresponds to o' in the transposed convolution case), but we could maybe make that clearer by making use of relationship 2 on the direct convolution view:

\tilde{i}' = i' + (s - 1)(i' - 1),
        o' = (\tilde{i}' - k') + 2p' + 1
           = (i' + (s - 1)(i' - 1) - k) + 2(k - p - 1) + 1
           = s(i' - 1) + k - 2p

from conv_arithmetic.

Yeah, the equation for o should use i, not i'. And you probably want to lose the tildes too.

from conv_arithmetic.

If i' contains a multiplication by s then you have an s^2 term in there, don't you?

from conv_arithmetic.

I'm not sure I understand what you mean.

from conv_arithmetic.

What exactly is i' in this situation? I see only tilde-i'.

On Thu, Mar 31, 2016 at 1:02 PM, vdumoulin [email protected] wrote:

I'm not sure I understand what you mean.

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#2 (comment)

from conv_arithmetic.

i' corresponds to the input size of the transposed convolution or, alternatively, the output size of the converse convolution.

from conv_arithmetic.