Does it work with vanilla Spring 4/5 about jasypt-spring-boot HOT 12 CLOSED

It should work, @EnableEncryptableProperties imports some configuration that registers a BeanFactoryPostProcessor to decorate property sources present in the Environment.
@EncryptablePropertySource is simpler, it just enables one specific property source with jasypt capabilities.
Do you have (or can create) a test app in Github where the problem manifests?

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@ulisesbocchio Thanks for the reply.
I will upload a sample later.

But I saw the spring-boot package get used in the EnableEncryptablePropertySourcesPostProcessor.java, could it be a problem?

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Here is ref repo:
https://github.com/chenrui333/jyspert-spring-sample

The command line to run is ./gradlew appRun

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jasypt-spring-boot does not work with vanilla Spring as properties source loading is different,
Spring Boot used PropertySourceLoader, while vanilla Spring used PropertySourcesPlaceholderConfigurer

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Alright, let me take a look at your project...sorry for the delay

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Thanks.

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Any update?

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I'll get back to you today... sorry for the delay

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You're missing this in your TestConfig:

@Bean
    PropertySourcesPlaceholderConfigurer propertySourcesPlaceholderConfigurer() {
        return new PropertySourcesPlaceholderConfigurer();
    }

That's mandatory if you want to enable PropertySources in general. Basically, without that bean, not even Spring's @PropertySource annotation works. In Spring Boot, there's an auto configuration for it in org.springframework.boot.autoconfigure.PropertyPlaceholderAutoConfiguration

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Let me re-try it.
UPDATE:
Works pretty good! Thanks!

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Another quick question is that whether I can use gradle to setup system property that it can be picked up by Spring configuration.

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you gotta pass the system property to tomcat or whatever servlet container you're using when you run your application if you use it out of the box. Otherwise you can define your own SpringEncryptor bean and retrieve the password from wherever you want.

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