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Taywee avatar Taywee commented on July 29, 2024

Not easily with an enum. Remember that an enum is basically an integer, and you are trying to switch the return type based on the integer value sent into it. You'd have to make the enum members actually different classes to properly switch in this way, that way they can be correctly overridden to give you the right return value:

#include <iostream>
#include <string>

template <typename T>
class eSetting {
};

eSetting<bool> flagA;
eSetting<bool> flagB;
eSetting<bool> flagC;
eSetting<std::string> valueFlagA;
eSetting<std::string> valueFlagB;
eSetting<int> valueFlagC;

template <typename T>
T function(const eSetting<T> &flag) {
    std::cout << "This is the default value" << std::endl;
    return T();
}

template <>
bool function<bool>(const eSetting<bool> &flag) {
    std::cout << "This is the overridden boolean value" << std::endl;
    return true;
}

int main(int argc, char **argv)
{
    function(flagA);
    function(flagC);
    function(valueFlagA);
    function(valueFlagC);
    return 0;
}

If you actually need an enum, it might be a bit more difficult. You can not encode that kind of type information on an enum, but you could use template specialization to switch directly based on the enum members, though you might need another template struct to switch correctly on the type at compile time, but it ends up looking quite unpleasant:

#include <iostream>
#include <string>

struct Foo {
    // Enum declaration
    enum class eSetting {
        flagA,
        flabB,
        flagC,
        valueFlagA, // str
        valueFlagB, // str
        valueFlagC // int
    };

    // Return type specializations.  This acts as a compile-time map to map
    // enum values to their return types
    template <eSetting Setting>
        struct eSettingTypes {};

    // Set up get function specializations
    template <eSetting Setting>
        typename eSettingTypes<Setting>::type get();
};

template <>
struct Foo::eSettingTypes<Foo::eSetting::flagA> {
    typedef bool type;
};
template <>
struct Foo::eSettingTypes<Foo::eSetting::valueFlagA> {
    typedef std::string type;
};

template<>
bool Foo::get<Foo::eSetting::flagA>() {
    std::cout << "flagA" << std::endl;
    return true;
}

template<>
std::string Foo::get<Foo::eSetting::valueFlagA>() {
    std::cout << "valueFlagA" << std::endl;
    return "";
}

int main(int argc, char **argv)
{
    Foo foo;
    foo.get<Foo::eSetting::flagA>();
    foo.get<Foo::eSetting::valueFlagA>();
    return 0;
}

This also would force you to create a specialization of both the type structure and the get function for each setting.

from args.

mr-potato-head avatar mr-potato-head commented on July 29, 2024

Awesome ! The first one seems to be perfect for my use case ;) Thank you so much.

from args.

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