Timezone from OpenWeatherMap has changed, Watchy hasn't. about watchy HOT 4 OPEN

Geolocation would be nice for sunset and tidal calculation also

But yes, https://openweathermap.org/current#geo looks like they haven't bumped api numbers

from watchy.

In case it's helpfull to anyone:

(1) OpenWeatherMap has always returned gmtOffset in seconds, and this is what Watchy requires/expects, so the original line: gmtOffset = int(responseObject["timezone"]);
is correct.

(2) The way I fixed the “City ID has been discontinued, Geo-Location (longitude and latitude) is required” issue is:

(a) Edit “settings.h” to:

#define OPENWEATHERMAP_URL "http://api.openweathermap.org/data/2.5/weather?lon=-0.12&lat=51.5"
(or whatever longitude and latitude you want is)

(b) Edit “Watchy.cpp” to:

    String weatherQueryURL = url + String("&units=") + units +
                             String("&lang=") + lang + String("&appid=") +
                             apiKey; // edited
    http.begin(weatherQueryURL.c_str());
    int httpResponseCode = http.GET();
    if (httpResponseCode == 200) {
      String payload             = http.getString();
      payload=payload.substring(payload.indexOf('{')); // edited/added
      JSONVar responseObject     = JSON.parse(payload);
      currentWeather.temperature = int(responseObject["main"]["temp"]);
      ...

(this works as at 11Sept2023)

from watchy.

Instead of using static Longitude and Latitude, you can use the same payload method of reading the JSON from this URL: http://ip-api.com/json/?fields=lat,lon

And merging the results into the OPENWEATHERMAP_URL by making lon=#1&lat=#2 and replacing #1 & #2 with the results from the above URL after parsing it's JSON. This is how Watchy GSR does it.

from watchy.