Comments (3)
lemonbench的原生问题,有空看看也许能修复
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应该已修复,你看再测一次看看
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之前那个写入IOPS的计算是通过写入次数除以写入时间得到的:
DiskTest_WriteIOPS="$(echo ${DiskTest_WriteTime} $3 | awk '{printf "%d\n",$2/$1}')"
这种计算方法在大部分情况下是有效的,但对于较小的块大小和较大的写入次数,有偏差
因为IOPS是对每秒钟的读/写操作次数,而块大小和写入次数会影响到每个操作的大小。当块大小较小且写入次数较大时,每个操作的大小会减小,导致IOPS计算的结果偏小。
为了准确地计算IOPS,已经将写入操作的大小(块大小)与写入时间结合,得到总的写入字节数,然后将其除以写入时间来计算IOPS,这思路应该没毛病了
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