Kaplan Meier output consistent regardless of time about scikit-survival HOT 6 CLOSED

Your code looks good. I tried to reproduce your problem but couldn't.

• can you print version of sksurv (import sksurv as sks; sks.__version__)?
• Can you restart your kernel, then try the following snippet and paste the output?

%matplotlib inline
import matplotlib.pyplot as plt
from sksurv.nonparametric import kaplan_meier_estimator

import pandas as pd

df = pd.DataFrame(
    {'Canc': [False, False, True, False, True, False],
     'days': [693, 298, 52, 365, 361, 307]})
y = df.to_records(index=False)

time, survival_prob = kaplan_meier_estimator(y["Canc"], y["days"])
plt.step(time, survival_prob, where="post");

from scikit-survival.

Interesting - when trying to print the version on sksurv it states 'unknown'. I think this is because I had to add a line of code '# coding: utf-8' to the top of the .py file 'nonparametric' in the package to fix this error:

have you seen this error before? If so, what did you do to deal with it?

When I copied in your code I got this:

from scikit-survival.

Adding # coding: utf-8 should not be necessary with Python 3, which handles utf-8 encoded files by default, which suggests you are mixing Python 2 and 3.

Could you please post more details about your setup, please:

• How did you install scikit-survival?
• What's your Python version?
• What's your numpy version?
• What's your scipy version?
• What's your matplotlib version?

You can use pandas.show_versions().

from scikit-survival.

My python version is 2.7
Numpy version is 1.13.1
Scipy version is 0.19.1
Matplotlib version is 1.5.3

I do not have administrative rights on my computer so someone else downloaded scikit-survival for me but I'm assuming they installed it using pip.

from scikit-survival.

Python 2 is not supported, only Python 3. Could you please try your example in a Python 3 environment?

from scikit-survival.

I'm closing this issue as no further information has been provided. Please feel free to reopen this issue if you can provide the requested information.

from scikit-survival.