Get lxml node (HtmlElement) about parsel HOT 8 CLOSED

If you want the element itself, you have to do h1 = sel.xpath(".//div/h1")[0].
You use extract() or extract_first() when you're only interested in the extracted content.

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Ok, but i get parsel.selector.Selector:

>>> h1 = sel.xpath(".//div/h1")[0]
>>> type(h1)
<class 'parsel.selector.Selector'> # but no lxml.html.HtmlElement

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From the selector, use the root attribute to get the lxml element.

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From the selector, use the root attribute to get the lxml element.

Thanks. this make my day 👍 (may be add this to docs?)

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Could be a nice addition to the docs, but I'd rather have a decision on #40 first, but I'd review a PR to the docs if you want to add something. :)

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Yes, first i get <class 'lxml.etree._Element'> instead <class 'lxml.html.HtmlElement'>.
Maybe change this line:

from lxml import etree, html
...
def create_root_node(text, parser_cls, base_url=None):
    ...
    return html.fromstring(body, base_url=base_url)

That is call function fromstring from the package lxml.html but not lxml.etree

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@mega7star see #40

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Using Parsel from master, you're now able to get lxml.html.HtmlElement as we've switched to html.HTMLParser on #63

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