Comments (3)
Schema.org has no required properties nor values for classes. That's why you can not find these on its site.
If you want to know what a data consumer like Google requires you will have to read their documentation: https://developers.google.com/search/docs/appearance/structured-data/search-gallery
from schemaorg.
yeah, you right
from schemaorg.
Yes - nothing is mandatory from Schema.org's perspective
Think of us as being a bit like a dictionary - you wouldn't let your dictionary tell you what to say. Schema.org focuses on the meaning of terms. The documentation at the search engine sites and elsewhere will be clearer about the kinds of information they need in order to offer different kinds of service or features.
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Related Issues (20)
- Add Season, Diet, Course and Allergen
- change recipeIngredient from text to custom object
- Consider supporting RDF-star and JSON-LD-star for temporal aspects of properties (and deprecating Role) HOT 3
- Content negotiation for JSON-LD (or TTL) representation HOT 6
- Correct usage of usageInfo HOT 1
- Support values of type TextObject for the name property to allow tagging of names as being AI generated
- Make RDF available under prefix URL
- authors HOT 1
- Many Place properties are not relevant to AdministrativeArea / City
- adas.it HOT 1
- Inquiry About Using "sameAs" Property for Knowledge Graph Entities
- The program cannot read my link URL, while Google can still read it
- Is creditText to be used for Acknowledgements?
- Clean-up PaymentMethod
- Improve markup for electric vehicles
- Incorrect phone numbers
- Let all types has the https://schema.org/additionalProperty
- PROTEGÉ Y SHEMA.ORG
- Extend 'MerchantReturnPolicySeasonalOverride' to enable overrides of more properties
- Update to Schema.org site HOT 12
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