[Question] How to integrate with external apps like celery about watchfiles HOT 4 CLOSED

In case if you are looking for solution in 2022:

watchfiles "celery  -A config.celery_app worker -l INFO" src

from watchfiles.

Answer:
watchgod celery.__main__.main --args -A config.celery_app worker -l INFO

from watchfiles.

Sorry for the slow response.

Not enough information here to help much I'm afraid.

from watchfiles.

I like @emilecaron 's answer better but you can also write a small function to start celery in worker mode and invoke it with watchgod.

tasks.py

celery_app = Celery(__name__)

def run():
   celery_app.start(argv=["worker", "-l", "INFO" ])

Then

watchgod tasks.run

I haven't figured out how to pass works with the --args flag though. The start method is supposed to use sys.args if no argv was provided but it doesnt seem those are progpagated in a functional way.

from watchfiles.