Comments (1)
Without iterating through at all, I don't think so. With just printing them I have:
#include "cppitertools/combinations_with_replacement.hpp"
#include <iostream>
#include <vector>
int main() {
const std::vector<int> v = {3, 7};
for (auto &&ns : iter::combinations_with_replacement(v, 4)) {
std::cout << "{ ";
for (auto i : v) {
std::cout << std::count(ns.begin(), ns.end(), i) << ' ';
}
std::cout << "}\n";
}
}
For one object that you can iterate through:
#include "cppitertools/combinations_with_replacement.hpp"
#include "cppitertools/imap.hpp"
#include <iostream>
#include <vector>
int main() {
const std::vector<int> v = {3, 7};
auto counts = iter::imap([&v](auto&& ns) {
return iter::imap([&ns](auto i) {
return std::count(std::begin(ns), std::end(ns), i);
}, v);
}, iter::combinations_with_replacement(v, 4));
// then to iterate over it and display
for (auto&& c : counts) {
std::cout << "{ ";
for (auto i : c) {
std::cout << i << ' ';
}
std::cout << "}\n";
}
}
The above still iterates through it with the call to std::count
of course.
from cppitertools.
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