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Comments (4)

xueyongwei avatar xueyongwei commented on June 1, 2024 1

No nessary.

from rxbinding.

lm2343635 avatar lm2343635 commented on June 1, 2024

I am not sure what you want to implement.
You mean
a <~ b == b.bind(to: a) ??

from rxbinding.

geonu1109 avatar geonu1109 commented on June 1, 2024

a <~ b == b.bind(to: a)
Correct! It's what I want to say.

from rxbinding.

lm2343635 avatar lm2343635 commented on June 1, 2024

I think adding the operator <~ makes the operators confused to understand.
Because we have a two-way binding operator <~>.
Even it is a two-way binding operator, we have to use it according to order, just like:

BehaviorRealy <~> ControlValue

You can confirm the implementation of the two way binding method.
The operator <~ makes it possible to reverse the binder and observable object.
However, I do not hope to reverse for the operator <~>.
For this reason, close this issue.

from rxbinding.

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