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bluss avatar bluss commented on June 8, 2024

An adaptor for product is a good idea, I guess it's the most natural way to use it. Not sure if we can make it expand tuples like the iproduct macro does (((x, y), z) → (x, y, z)).

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alexchandel avatar alexchandel commented on June 8, 2024

That would be preferable, but I think it requires variadic generics, or at minimum having two impls, one for Item=A and one for Item=(A,B).

I'd be satisfied with the basics for now. I can always map(|((x,y),z)| (x,y,z)) until then.

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bluss avatar bluss commented on June 8, 2024

Is there any reason to prefer the long name cartesian_product? I.e. are there other products we might want to add?

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alexchandel avatar alexchandel commented on June 8, 2024

@bluss Can't think of any others (not that there aren't any), but we want to avoid product() because it's taken by MultiplicativeIterator. times() would work too, though it's less specific.

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FranklinChen avatar FranklinChen commented on June 8, 2024

Something else very useful is a Cartesian product without a hardcoded length, i.e., concretely something like taking a vector of iterators and returning a iterator of vectors: a form of Haskell's sequenceA, where

sequenceA [[0..2], [0..2], [0..2]] == [[0,0,0],[0,0,1],[0,0,2],[0,1,0],[0,1,1],[0,1,2],[0,2,0],[0,2,1],[0,2,2],[1,0,0],[1,0,1],[1,0,2],[1,1,0],[1,1,1],[1,1,2],[1,2,0],[1,2,1],[1,2,2],[2,0,0],[2,0,1],[2,0,2],[2,1,0],[2,1,1],[2,1,2],[2,2,0],[2,2,1],[2,2,2]]

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