How add modifer to total sum in multi instruction? about diceparser HOT 5 CLOSED

The error is on $2d5, as $2 could be 0 and 0d5 leads to error.

The command you want is:

!2d10;$1i.[=10]{+1d5};$2+5;"Final result: $3"

The explode operator does not support sub-operation yet. It will be possible soon to do it like this:

!2d10e10(1d5)+5

from diceparser.

2d10;$1c[=10];$2d5 this works perfect and count separatrly notmal sum and crit sum.

i want to add +5 on normal sum, not critical sum.
2d10+5 <- this one brakes in joined statement !2d10+5;$1c[=10];$2d5

from diceparser.

thank you now formula works properly
!2d10;$1c[=10];$2i:[>0]{$2d5};$1+4;"normal damage $4, critical damage $3"

however there is still problem with adding + bonus to first case. (in example above i just moved that operation to sepparate case)
!2d10+4;$1c[=10];$2i:[>0]{$2d5};$1+0;"normal damage $4, critical damage $3"
here $3 is always 0 even if 2d10 both 10

from diceparser.

it is because this can't worked: 2d10+4;$1c[=10]

in diceparser, each instruction has a result.
Diceparser manages 3 types of result: dicelist, number and string
The result type of: 2d10 is dicelist.
The result type of: 2d10+4 is number (assuming you want to roll 2 dice, sum their values and add 4.

Count operator (c) works on dicelist only. If previous result isn't dicelist, it does nothing.

from diceparser.

got it, thanks

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