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jMarcS avatar jMarcS commented on July 17, 2024

What is the failure? What type of object are you trying to get when it fails?
When you use your workaround, what changes?
How did you choose the argument of indexOf and what does it mean?

It's not at all clear to me what you're doing or why.

from basic.

olimaticer avatar olimaticer commented on July 17, 2024

It's not at all clear to me what you're doing or why.

I was getting numeric arrays from a bundle.
I have to deside what type of numeric array value is to convert it into Double.

Many thanks for your questions!
After a creative distance from some days I found my mistake.
I am working with an object array Object[] !!!
After printing object.toString() i got "[D@abcd...". It seems that
[ stands for an array maybe --> Class
D for the type Double --> Name
@ is a delimiter
and the rest is the hashCode().
getClass().getName() + '@' + Integer.toHexString(hashCode())

from basic.

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