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Comments (2)

bazinga-web avatar bazinga-web commented on June 21, 2024

注意:array.prototype.includes方法复杂度为O(n),可使用Map Set .has()方法代替,复杂度为O(1)

/**
 * @param {number[]} nums1
 * @param {number[]} nums2
 * @return {number[]}
 */
var intersection = function (nums1, nums2) {
    let result = new Set();
    let sort = new Set(nums2);
    for (num of nums1) {
        if (sort.has(num)) {
            result.add(num);
        }
    }
    return Array.from(result);
};

from like-algorithms.

Ray-56 avatar Ray-56 commented on June 21, 2024

哈希表

/**
 * @param {number[]} nums1
 * @param {number[]} nums2
 * @return {number[]}
 */
var intersection = function(nums1, nums2) {
	// 哈希表
	const ret = [];
	const set = new Set(nums1);
	for (let n of nums2) {
		if (set.has(n) && !ret.includes(n)) {
			ret.push(n);
		}
	}
	return ret;
};

from like-algorithms.

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