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bazinga-web avatar bazinga-web commented on August 13, 2024

解题思路:

  1. 新开一个结果数组,初始值均为1,长度与nums相同
  2. 从左至右遍历nums,将从最左边到达i项的乘积值放入nums[i]
  3. 从右向左遍历nums,执行同样的逻辑,即可得到result
/**
 * @param {number[]} nums
 * @return {number[]}
 */
var productExceptSelf = function (nums) {
    let result = new Array(nums.length).fill(1);

    let product = 1; // 保证统一性

    for (let i = 0; i < nums.length; i++) {
        result[i] = result[i] * product;
        product = nums[i] * product;
    }

    product = 1;

    for (let i = nums.length - 1; i >= 0; i--) {
        result[i] = result[i] * product;
        product = nums[i] * product;
    }

    return result;
};

from like-algorithms.

Ray-56 avatar Ray-56 commented on August 13, 2024

动态规划解

/**
 * @param {number[]} nums
 * @return {number[]}
 */
var productExceptSelf = function(nums) {
    const len = nums.length;
	const dp1 = Array(len).fill(0);
	dp1[0] = 1;

	for (let i = 1; i < len; i++) {
		dp1[i] = dp1[i - 1] * nums[i - 1];
	}
	
	const dp2 = Array(len).fill(0);
	dp2[len - 1] = 1;
	for (let i = len - 2; i >= 0; i--) {
		dp2[i] = dp2[i + 1] * nums[i + 1];
	}
	
	const ret = [];
	for (let i = 0; i < len; i++) {
		ret[i] = dp1[i] * dp2[i];
	}
	return ret;
};

from like-algorithms.

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