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Ray-56 avatar Ray-56 commented on September 16, 2024

dp 解法

  • dp[i] = maxn 为 i 时 的最大乘积
  • i = j + (i - j)拆分 i ,乘积就是j * (i - j)但是不一定是最大的,与j * dp[i - j]相比得到最大乘积
  • 由题意可知前两个的最大乘积都为1
/**
 * @param {number} n
 * @return {number}
 */
var integerBreak = function(n) {
	const dp = Array(n + 1).fill(1);

	for (let i = 3; i <= n; i++) {
		for (let j = 2; j < i; j++) {
			dp[i] = Math.max(
				dp[i],
				j * (i - j),
				j * dp[i - j]
			);
		}
	}
	return dp[n];
};

from like-algorithms.

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