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Ray-56 avatar Ray-56 commented on August 13, 2024

从题意可知,最后的台阶不花费体力

复杂度为 O(N)

/**
 * @param {number[]} cost
 * @return {number}
 */
var minCostClimbingStairs = function(cost) {
	const len = cost.length;
	const dp = Array(len + 1);
	dp[0] = cost[0];
	dp[1] = cost[1];
	for (let i = 2; i <= len; i++) {
		if (i === len) {
			dp[i] = Math.min(dp[i - 2], dp[i - 1]);
		} else {
			dp[i] = Math.min(dp[i - 2], dp[i - 1]) + cost[i];
		}
	}

	return dp[len];
};

from like-algorithms.

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