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fingertree.js's Issues

Errors handling laziness in Deep.concat() and app3()

Deep.concat and app3() both do instanceof checks on their arguments and then access properties in them. You need to force the arguments if they're lazy, otherwise they fail the instanceof checks and default case in app3() fails on a property access.

For my CoffeeScript version, I just added a force method to FingerTree that returns this. Then, at the top of Deep.concat() and app3(), I just reassigned the arguments to be their forced versions.

incorrect behavior when implementing simple priority queue

@qiao,

Here is my max-priority queue test.

It should sort [1,3,2,9,7] into [9,7,3,2,1] and print it out.

var FingerTree = require('fingertree');

// Create a finger-tree with a custom measurer.
var measurer = {
    identity: function () {
        return -Infinity;
    },
    measure: function (x) {
        return x;
    },
    sum: function (a, b) {
        return Math.max(a, b);
    }
};
var maxTree = FingerTree.fromArray([1, 3, 2,  9, 7], measurer);

var i = 1;
while(!maxTree.isEmpty()) {
    //console.log("tree: ",JSON.stringify(maxTree.toJSON(),null,2));
    var split = maxTree.splitTree(function(measure) {
        return measure>=maxTree.measure()
    },-Infinity);
    console.log(i+") "+split.mid+"; max:"+maxTree.measure()+" left:"+split.left.measure()+" right:"+split.right.measure());
    //console.log("left: ",JSON.stringify(split.left.toJSON(),null,2));
    //console.log("right: ",JSON.stringify(split.right.toJSON(),null,2));
    maxTree = split.left.concat(split.right)
    i++;
}

But it prints

1) 9; max:9 left:3 right:7
2) 7; max:7 left:3 right:2
3) 3; max:3 left:1 right:2
4) 2; max:2 left:1 right:2
5) 2; max:2 left:1 right:-Infinity
6) 1; max:1 left:-Infinity right:-Infinity

So I consider there is some bug in splitTree when item actually does not get removed from left/right subtree. You can uncomment console.log and you will see that after removing 7 the element 2 is both in right subtree and left subtree. Therefore it is printed twice, while source array contained only single element "2".

Could you please comment what I'm doing wrong??

Regards, mikhail.

bug in `nodes`

It there a reason why it is assumed that xs.length <= 8 here? There is no such assumption in Hinze and Paterson.

const FingerTree = require( 'fingertree' ) ;
let X = FingerTree.fromArray( [ ] ) ;
for ( let i = 0 ; i < ( 4 * 4 + 4 ) ; ++i ) X = X.addLast( i ) ;
let Y = FingerTree.fromArray( [ ] ) ;
for ( let i = 0 ; i < ( 4 * 4 + 4 ) ; ++i ) Y = Y.addFirst( i ) ;
X.concat( Y ).measure( )
Error: invalid number of nodes
    at nodes (/home/aureooms/node_modules/fingertree/src/fingertree.js:994:22)
    at DelayedFingerTree.thunk (/home/aureooms/node_modules/fingertree/src/fingertree.js:963:35)
    at DelayedFingerTree.force (/home/aureooms/node_modules/fingertree/src/fingertree.js:794:24)
    at DelayedFingerTree.measure (/home/aureooms/node_modules/fingertree/src/fingertree.js:810:17)
    at FingerTree.Deep.measure (/home/aureooms/node_modules/fingertree/src/fingertree.js:576:52)
    at DelayedFingerTree.measure (/home/aureooms/node_modules/fingertree/src/fingertree.js:810:25)
    at FingerTree.Deep.measure (/home/aureooms/node_modules/fingertree/src/fingertree.js:576:52)
    at repl:1:15
    at REPLServer.defaultEval (repl.js:164:27)
    at bound (domain.js:250:14)

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