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Comments (3)

PisecesPeng avatar PisecesPeng commented on September 26, 2024

解题思路

  • 遍历链表直到尾端, 然后再从尾端开始向前构造链表

代码

class ListNode {
    int val;
    ListNode next;
    ListNode(int x) {
        val = x;
    }
}
public static ListNode func(ListNode head) {
    if (head == null) return null;

    ListNode point = new ListNode(0);
    reverse(head, point);
    return point.next;
}

public static ListNode reverse(ListNode listNode, ListNode point) {
    ListNode val = new ListNode(listNode.val);
    ListNode tmp;
    // 一旦递归到链表末尾, 就开始回溯构造链表
    if (listNode.next != null)
        tmp = reverse(listNode.next, point);
    else
        tmp = point;
    tmp.next = val;
    return tmp.next;
}

from pisecespeng.record.me.

PisecesPeng avatar PisecesPeng commented on September 26, 2024

LeetCode题解

解题思路

  • 递归, 遍历到尾端再从尾到头构造链表

代码

class ListNode {
    int val;
    ListNode next;
    ListNode(int x) {
        val = x;
    }
}
public ListNode func(ListNode head) {
    if (head == null || head.next == null) {
        return head;
    }
    ListNode newHead = func(head.next);
    head.next.next = head;
    head.next = null;
    return newHead;
}

from pisecespeng.record.me.

PisecesPeng avatar PisecesPeng commented on September 26, 2024

LeetCode题解

解题思路

  • 迭代, 在遍历的同时构造前后结点的关系

代码

class ListNode {
    int val;
    ListNode next;
    ListNode(int x) {
        val = x;
    }
}
public ListNode func(ListNode head) {
    ListNode prev = null;
    ListNode curr = head;
    while (curr != null) {
        ListNode next = curr.next;
        curr.next = prev;
        prev = curr;
        curr = next;
    }
    return prev;
}

from pisecespeng.record.me.

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