How to run one or two commands? about baseimage-docker HOT 4 CLOSED

my_init is supposed to run all of the runit scripts, not just one script...

Why don't you create a runit script and put it in image/runit?
source ~/.bashrc at the beginning of your script if you need it
On Jun 12, 2014 10:58 PM, "disposable-ksa98" [email protected]
wrote:

I tried this and it works:

docker run -i -t myimage my_init -- echo 'lol'

But then I tried this and didn't work:

docker run -i -t myimage my_init -- cd /srv

What I really want to do is go to certain directory and then execute
certain script. The cd part already is supposed to happen in ~/.bashrc. Is
there a way to make my command execute after ~/.bashrc? If that's not
possible, I would like to simply run two commands: cd into that directory
and then execute the script.

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#91.

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This is not a baseimage-docker issue. You are misunderstanding how shell commands work. The arguments you pass to my_init are run directly by passing them to the operating system's exec() system call, so they don't constitute a shell command. If you want to change the working directory first, you need to run a shell command -- in other words, you need to wrap things in a bash call. Like this:

docker run -i -t myimage my_init -- /bin/bash -c 'cd /somewhere && some command here'

See also this: http://superuser.com/questions/241129/why-wont-sudo-cd-work

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@FooBarWidget Thanks, that works. So how would you do to run .bashrc and also "some command"?

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To run bashrc, pass -l to bash.

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