-i (path for include files) option for Linux compiler does not work about compiler HOT 4 CLOSED

Are you compiling from the same directory where compile.sh is? Try replacing relative paths with absolute ones, that definitely should help. You can get the absolute path to compiler.sh from within the script itself via something like $(dirname $(readlink $0)) (for example, see here) and append your include directory to that.

from compiler.

Are you compiling from the same directory where compile.sh is?

Yes.

Try replacing relative paths with absolute ones, that definitely should help. You can get the absolute path to compiler.sh from within the script itself via something like $(dirname $(readlink $0)) (for example, see here) and append your include directory to that.

I tried it, but it did not help.

I made small repo for test it: https://github.com/ziggi/pawn_linux_test
My new !compile.sh:

#/bin/bash

export LD_LIBRARY_PATH=$(pwd)"/compiler/:$LD_LIBRARY_PATH"

NAME="test"

include_path="$(dirname $(readlink -f $NAME))/compiler/includes"

./compiler/pawncc "-;+ -(+ -i$include_path" sources/$NAME.pwn

if [ $(stat -c%s "$NAME.amx") -gt 0 ];
then
    mv $NAME.amx gamemodes/
else
    rm $NAME.amx
fi

from compiler.

"-;+ -(+ -icompiler/includes"

You can't take multiple arguments in quotes like that, they will be treated as one string. Try this instead:

"-;+" "-(+" "-icompiler/includes"

from compiler.

Yeah, it's works. Thank you very much!

from compiler.