Comments (1)
My 127.0.0.1:5000 can not see anything. But the gstreamer show the window when I wave my hand in front of camera.
Is it the normal for 127.0.0.1:5000 doesnt show the image, but the gstreamer show the image?
What do you mean? 127.0.0.1:5000 is not a HTTP server showing the video, it's the address at which the media-receiver example forwards the video stream from the browser (see the example code here). You need to start gstreamer listening at the address to receive and decode the video stream.
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Related Issues (20)
- Callback for rtcSetGatheringStateChangeCallback sometimes not firing for RTC_GATHERING_COMPLETE HOT 3
- can't build on windows platform with VS2022 HOT 1
- Libnice on Windows HOT 4
- RTP H264/H265 de-packetization rule for lost fragments HOT 2
- Candidate parser is too order-dependent HOT 1
- Statistics for media transport
- TLS handshale failure with Mbed TLS 3.6.0 HOT 1
- Support multiple fingerprints in description
- double free when rtc::Track destructing HOT 7
- Invalid pointer casting in H264 packetizer HOT 3
- Order of media formats not preserved HOT 2
- Issue establishing a webrtc connection with mobile network HOT 1
- There is a chance of package lost in datachannel HOT 2
- Is this lib better than libwebrtc? HOT 1
- error C3861: 'juice_add_turn_server': identifier not found HOT 1
- h264rtpdepacketizer doesn't handle multiple NAL units with same timestamp HOT 1
- some questions about support for WebRTC Direct HOT 21
- when cross compiling for arm,tests and examples failed. HOT 5
- v0.21.0 fails to compile due to missing header HOT 1
- WebSocketServer stops running after a while. ``getsockname failed`` after a successful ``accept()``. HOT 2
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